Question

PQR is a right angle triangle,right angled at Q. if PQ=20cm and QR=21cm .find PR​

Answer 1

Answer:

The required value of $PR=29 cm$

Step-by-step explanation:

Right angle triangle:

A triangle is said to be right-angled if one of its inner angles is 90 degrees, or if any one of its angles is a right angle. The right triangle or 90-degree triangle is another name for this triangle.

Given: In a right angle $PQR$, ∠$Q=$ right angle, $PQ=20 cm$ and $QR=21 cm$

To find: The objective is to find out the value of $PR$.

Solution:

Using the formula of Pythagoras theorem:

$(Hypotenuse)^{2} =(Perpendicular)^{2} +(Base)^{2} \\(PR)^{2} =(PQ)^{2} +(QR)^{2} \\(PR)^{2} =(20)^{2} +(21)^{2} \\PR=\sqrt{400+441$

$PR=29$

Therefore, the required value of $PR=29 cm$

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Answer 2

Answer:

We'll use Pythagoras theorem to solve the given equation

Step-by-step explanation:

Pythagoras theorem:

⇒ $h^{2}$ = $p^{2} + b^{2}$ - (a)

Given, p = 20 cm, b = 21 cm - (b)

Putting values from (b) into equation (a)

⇒ $h^{2}$ = $(20)^{2} + (21)^{2}$

⇒ $h^{2}$ = 400 + 441

⇒ h = $\sqrt{841}$

⇒ h = 29 $cm^{2}$

Hence, using Pythagoras theorem, we found out hypotenuse to be equal to 29 $cm^{2}$

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