Question

PQR is a right angled triangle at P.ig PQ=10cm and PR=24 then find QR

​

Answer 1

i don't know it and sorry i can't help you

Answer 2

Answer:

${}^{ \sorry \: for \: reporting \: you \: ans. }$

Explanation:

We know that,

In a Right angled triangle: By Pythagoras theorem,

(Hypotenuse)² = (Base)²+(Perpendicular)²

As PQR is a right angled triangle with

Base = PQ = 10cm

Perpendicular = PR = 24cm

Hypotenuse = QR

So,by Pythagoras theorem

(QR)=(PQ)²+(PR)²

(QR)=(10)²+(24)²

(QR)²=100+576

(QR)²=676

QR=26cm

Hence, length od QR is 26cm Ans.

${}^{ \hope \: its \: help \: you. }$