PQR IS A RIGHT ANGLED TRIANGLE AT Q , IF PR = 17 CM AND PQ = 8 CM , THEN FIND THE VALUE OF 15 SEC P + I COT P
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Answer:
1. we have to find the perpendicular by
USIng Pythagoras theoram
hypotenus square = base square+perpendicular square
17×17-8×8=p square
289-64=perpendicular square
225=perpendicular square
p =15
then pu the value of sec and cot
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