Question

pqr is a right angled triangle such that PQ is 15 CM QR is 25 20 cm and PR is 25 cm find the area of the triangle length of the altitude corresponding to the hypotenuse​

Answer 1

Ans. area of triangle =1÷2×base×height

=1÷2×25×15

=375÷2

=187.5 sq .cm

Answer 2

Step-by-step explanation:

$area \: of \: triangle \: = \: \frac{1}{2} \times base \: \times height$

$\frac{1}{2} \times 20 \times 15$

$\frac{1}{2} \times 300$

$= 150 \: {cm}^{2}$