PQR is a right triangle right angled at Q. If QS = SR, show that PR' = 4PS-3PQ?
Answers
Answered by
2
Step-by-step explanation:
In the right angle ΔPQR, S is the midpoint of QR.
So QR² = PR² - PQ² and also
ΔPQS is right angled at Q.
So PS² = PQ² + QS²
= PQ² + QR²/4
= PQ² + (PR² - PQ²) / 4
= 3/4 * PQ² + PR² / 4
So PR² = 4 PS² - 3 PQ²
Pls Mark As Brainliest!
Happy Learning!
Stay Safe!
Answered by
0
Answer:
In the right angle ΔPQR, S is the midpoint of QR.
So QR² = PR² - PQ² and also
ΔPQS is right angled at Q.
So PS² = PQ² + QS²
= PQ² + QR²/4
= PQ² + (PR² - PQ²) / 4
= 3/4 * PQ² + PR² / 4
So PR² = 4 PS² - 3 PQ²
Similar questions