Math, asked by anugrah0, 7 months ago

PQR is a right triangle right angled at Q. If QS = SR, show that PR' = 4PS-3PQ?​

Answers

Answered by gayathreedeviaj
2

Step-by-step explanation:

In the right angle ΔPQR, S is the midpoint of QR.

So      QR² = PR² - PQ²  and   also

ΔPQS is right angled at Q.  

So  PS² = PQ² + QS²

             = PQ² + QR²/4

             = PQ²  + (PR² - PQ²) / 4

             = 3/4 * PQ² + PR² / 4                  

So PR² = 4 PS² - 3 PQ²

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Answered by viji18net
0

Answer:

In the right angle ΔPQR, S is the midpoint of QR.

So      QR² = PR² - PQ²  and   also

ΔPQS is right angled at Q.  

So  PS² = PQ² + QS²

            = PQ² + QR²/4

            = PQ²  + (PR² - PQ²) / 4

            = 3/4 * PQ² + PR² / 4                  

So PR² = 4 PS² - 3 PQ²

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