Question

PQR is a straight line. What is the value of x?​

Answer 1

Answer:

$\star\pink{Answer:-}⋆$

In the given fig., ∠PQA,∠AQB and ∠BQR forms a linear pair.

Therefore,

∠PQA+∠AQB+∠BQR=180°

(x+20°)+(2x+10°)+(x−10°)=180°

4x+20°=180°

⇒x=4180°−20°=40°

Therefore,

∠AQB=2x+10°=2×40°+10°=90°

∠BQP=(x+20°)+(2x+10°)=3x+30°=3×40°+30°=150°

∠AQR=(2x+10°)+(x−10°)=3x=3×40°=120°