Question

pqr is a traingle right angled at p and m is a point on qr such that pm perpemdicular qr.show that pm=qm.qr​

Answer 1

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Answer 2

Let angle PRQ = x and angle PQR = y

Then angle QPM = x and angle RPM = y ....................... complimentary angles

Triangles PMR and Triangle PMQ are similar triangles

Therefore MR/PM = PM/QM

MR * QM = PM * PM

Hence (PM)^2 = MR * QM

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