PQR IS A TRAINGLE RIGHT ANGLED AT P with PQ 6CM AND PR IS 8C. find the area of traingle and also find the length of perpendicular PS and QR
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if...
base -6cm
height-8cm
area of a triangle = b/2×h
=6/2×8
=24cm^2
length of QR( hypotenuse)...
PYTHAGORAS THEOREM...
(a)^2=(b)^2+(c)^2
(QR)^2=(PQ)^2+(PR)^2
=(6cm)^2+(8cm)^2
=36cm^2 + 64cm^2
(QR)^2 =100cm^2
QR=√100cm^2
QR=10cm
base -6cm
height-8cm
area of a triangle = b/2×h
=6/2×8
=24cm^2
length of QR( hypotenuse)...
PYTHAGORAS THEOREM...
(a)^2=(b)^2+(c)^2
(QR)^2=(PQ)^2+(PR)^2
=(6cm)^2+(8cm)^2
=36cm^2 + 64cm^2
(QR)^2 =100cm^2
QR=√100cm^2
QR=10cm
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