PQR is a triangle, Pq =pr. PS is angled bisector of angle p then show that PS bisects qr
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given- PQR is a ∆ where PQ=PR where PS is angle bisector of angle P
to prove - PS bisects QR i.e QS=SR
proof- in∆PSQ and ∆PSR
PQ=PR (given)
<QPS=<SPR (PS is angle bisector)
PS=PS (common)
hence both the triangles are congruent by SAS criteria
hence QS=SR (by c.p.c.t)
prooved
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harshini1997:
tq
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your answer is in the attachment hope it helps
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