Question

PQR is a triangle right angle at P if PQ =4cm and PR = 3cm

01. By using rule we can find PQ
a) SAS. b) AAA. c) Pythagoras d) None of these

02. Pythagoras rule ( side) ² +(side) ² = -------------
a) (PQ) ² b) (PR) ² c) (PQ +PR) ² d) ( QR) ²

03. If PR = 3 cm then PR ²=--------
a) 9 cm b) 9 cm ² c) 9 M. d) 9 m ²

04. If PQ = 4 cm PQ ² = -------
a) 4 cm ² b) 16 cm. c) 16 cm ² d) 16

05. We can apply the Pythagoras for ------------- triangle
a) Equilateral. b) scalene. c) Right d) none

06. Find the value of QR = ----------
a) 5 cm. b) 6 cm. c) 25 cm. d) 9 cm

Answer 1

Answer:

gPQ) ² b) (PR) ² c) (PQ +PR) ² d) ( QR) ²

03. If PR = 3 cm then PR ²=--------

a) 9 cm b) 9 cm ² c) 9 M. d) 9 m ²

04. If PQ = 4 cm PQ ² = -------

a) 4 cm ² b) 16 cm. c) 16 cm ² d) 16

05. We can apply the Pythagoras for ------------- triangle

a) Equilateral. b) scalene. c) Right d) none

06. Find the value of QR = -----