pqr is a triangle right angled at P and M is a point on QR such that PM is perpendicular to QR show that PM square is equals to QM into MR
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Question:
PQR is a triangle right angled at P and M is a point on QR such that PM is perpendicular to QR. show that PM^2 = QM × MR.
Refer to the attachment for figure
Solution:
We know the theorem that,
If a perpendicular is drawn on hypotenuse from the 90 degree vertex then the triangles on both side of this perpendicular are similar to each other.
therefore,
∆ PMR ~ ∆ QMP
so,
PM /QM = MR / PM
( being corresponding parts of similar triangles)
cross multiplying we will get
PM^2 = MR × QM
Hence proved.
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