PQR is a triangle, right angled at P. if PQ= 10 cm and PR= 24 cm find QR.
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50
this is answer of ur question
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31
hi friend! Here is ur answer
QR^2=PQ^2+RP^2
QR^2=10^2+24^24
QR=26
hope it helps u@@@
QR^2=PQ^2+RP^2
QR^2=10^2+24^24
QR=26
hope it helps u@@@
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