Question

pQr is a triangle, right-angled at p. if pQ =10 cm and PR=24 cm, find QR​

Answer 1

ANSWER

Given: PQ=10cm, PR=24cm

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse)square = (Base)square +(Perpendicular)square

[By Pythagoras theorem]

⇒(QR)square =(PQ)square + (PR)Square

⇒(x )square =(10)square +(24)square

⇒(x )square = 100+576=676

⇒x= 676

x=26cm

Thus, the length of QR is 26cm.

Answer 2

Answer:

fysjz kk dulcldkskgdls kk skfaktskt