PQR is a triangle, right angled at p. if PQ=10cm and PR=24cm, find QR
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PQ=10cm
PR=24cm
by pythagoras theorem PQ^2+PR^2=QR^2
10^2+24^2=QR^2
100+576=QR^2
676=QR^2
QR= root of 676
QR=26cm
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