Question

PQR is a triangle right angled at P if PQ =10cm and PR=24cm, find QR​

Answer 1

Answer:

Step-by-step explanation:

Given: PQ=10cm, PR=24cm

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse)2  =(Base)  2 +(Perpendicular)  2   [By Pythagoras theorem]

⇒(QR)  2  =(PQ)  2  +(PR)  2

 ⇒x  2  =(10)  2  +(24)  2

 ⇒x  2  =100+576=676

⇒x=  676

​   =26cm

Thus, the length of QR is 26cm.

Answer 2

If it is right-angled at P then the side opposite to P will be the hypotenuse of the triangle i.e. QR and the other sides are given as PQ = 10 cm and PR = 24 cm.

Now, by applying the Pythagoras theorem i.e. in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides, we can find QR.

Given, PQ = 10 cm, PR = 24 cm and QR =?

By applying Pythagoras theorem in triangle PQR, we get (Hypotenuse)2 = (Perpendicular)2 + (Base)2

(QR)2 = (PQ)2 + (PR)2

(QR)2 = (10)2 + (24)2

(QR)2 = 100 + 576

(QR)2 = 676

QR = 26 cm

Thus, QR is equal to 26 cm.