Question

PQR is a triangle, right angled at P. If PQ=10cm and PR= 24cm. Find QR

Full explanation and proper format..

Answer 1

Answer:

QR=26cm

Step-by-step explanation:

BY PYTHAGORAS THEOREM

QR^2=PR^2+PQ^2

QR^2=24^2+10^2

QR^2=576+100

QR^2=676

QR=√676

QR=26CM

Answer 2

$\huge\mathbb{QUESTION}$

PQR is a triangle, right angled at P. If PQ=10cm and PR= 24cm. Find QR?

$\huge\mathbb{ANSWER}$

According to the question we have to find the QR?

$\huge\bold{\red{Solution}}$

Base (PQ)= 10cm

Altitude (PR)= 24cm

Hypotenuse (QR)= ?

$\bold{\purple{Formula}}$

By phythogaras property,

$\bold{\blue{(Hypotenuse^2)= Base^2+Altitude^2}}$

$\bold{ \green{QR^2= PQ^2+RP^2 }}$

$\bold{ \purple{QR^2= 10^2+24^2 }}$

$\bold{ \orange{QR^2= 100+576 }}$

$\bold { \pink{QR^2= 676 }}$

$\bold{ \red{QR= \sqrt{676} }}$

$\bold{\green{ \sqrt{2 \times 2 \times 13 \times 13} }}$

$\bold{\purple{ 2 \times 13 = 26}}$

$\therefore\bold{Hypothenuse \: QR= 26}$

Khadijah21