Question

PQR is a triangle, right angled at P if PQ=10cm and PR=24cm find QR

Answer 1

using Pythagoras theorem here, we have

PR²=PQ²+QR²,

24²=10²+PR²,

24²-10²=PR²,

then

PR²=(24+10)(24-10),

PR²=34×14,

PR²=476,

PR=√476,

PR=21.81