PQR is a triangle ,right-angled at P. If PQ =10cm and PR=24cm , find QR.
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Here Is Your Answer My Friend ♥️♥️
(H)^2 = (P)^2 + (B)^2
(H)^2 = (24)^2 + (10)^2
(H)^2 = 576 + 100
(H)^2 = 676
H = √26 × 26
H = 26cm.
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@Shona...❣️❣️
(H)^2 = (P)^2 + (B)^2
(H)^2 = (24)^2 + (10)^2
(H)^2 = 576 + 100
(H)^2 = 676
H = √26 × 26
H = 26cm.
Hope It Help You..
Please Mark Me As Brainlest ♥️♥️
@Shona...❣️❣️
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arpit916:
thankyou very very much for this answer
happy bday
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