Math, asked by ashiasghar0810, 12 days ago

PQR is a triangle, right-angled at p. if PQ=10cm andPR=24cm, find QR​

Answers

Answered by ajajit9217
0

Answer:

Value of QR is 26 cm.

Step-by-step explanation:

Given:

ΔPQR is a right angled triangle.

∠P=90° So, QR is hypotenuse.(as side opposite to 90° is hypotenuse)

PQ=10 cm.

PR=24 cm.

According to pythagorean theorem,

Hypotenuse=QR= \sqrt{base^{2} +perpendicular^{2} }

                    =\sqrt{PQ^{2} +PR^{2} }=\sqrt{10^{2} +24^{2} } }

                     =\sqrt{100+576}=\sqrt{676}=26 cm.

Answered by preeti353615
0

Answer:

PQR is a triangle, right-angled at p. If PQ=10cm and PR=24cm, then QR​= 26 cm.

Step-by-step explanation:

PQR is a triangle, right-angled at angle P.

By Pythagoras theorem

QR^2 = PQ^2 + PR^2

if PQ=10cm and PR=24cm, find QR​

QR^2 = PQ^2 + PR^2\\=10^2 + 24^2\\= 100 + 576\\= 676\\QR = \sqrt{676} \\QR = 26 cm

So the length of QR is 26 cm.

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