Question

PQR is a triangle, right-angled at P. ifPQ= 10cm and PR = 24 cm, find QR​

Answer 1

$\boxed {\blue {ʀᴇғᴇʀ\: ᴛᴏ\: ᴛʜᴇ\: ᴀʙᴏᴠᴇ\: ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ}}$

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$\underline {\orange {\mathtt {Note:-}}}$

➜ɪғ ʏᴏᴜ ғᴇᴇʟ ᴀ ʙɪᴛ ᴄᴏᴍᴘʟɪᴄᴀᴛᴇᴅ ᴛᴏ ғɪɴᴅ ᴛʜᴇ sǫᴜᴀʀᴇ ʀᴏᴏᴛ ᴏғ 26 ,ʏᴏᴜ ᴄᴀɴ ɢᴏ ғᴏʀ ᴘʀɪᴍᴇ ғᴀᴄᴛᴏʀɪsᴀᴛɪᴏɴ ᴍᴇᴛʜᴏᴅ !!

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Hope it helps ✌️❣️

Answer 2

$\underbrace {Answer}$

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$\fbox \orange {Given:}$

PQ=10cm, PR=24cm

Let QR be x cm.

$\boxed {\pink {In\: right\: angled\: triangle\: QPR}}$

$\text {(Hypotenuse)^2 = (Base)^2 +((</p><p>perpendicular)^2}$

$\text {{(QR)}^2 = {(PQ)}^2 +{(PR)}^2}$

$\text {{(X)}^2 = 100+576}$

$\text {{(X)}^2 = 676}$

$\text {X= {(676)sqrt}}$

$\text {X= 26}$

$\fbox {\purple {Thus}}$

The length of QR is 26cm.

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