Question

PQR is a triangle right angled at P with PQ = 6cm and PR = 8cm.Find the area of triangle PQR. Also find the length of perpendicular PS on PR.

Answer 1

base -6cm
height-8cm


area of a triangle = b/2×h
=6/2×8
=24cm^2


length of QR( hypotenuse)...


PYTHAGORAS THEOREM...
(a)^2=(b)^2+(c)^2


(QR)^2=(PQ)^2+(PR)^2

=(6cm)^2+(8cm)^2
=36cm^2 + 64cm^2
(QR)^2 =100cm^2

QR=√100cm^2
QR=10cm

Hope it helps u

Answer 2

Answer:

area of a triangle = b/2×h = 6/2×8 = 24cm

(6cm)2+(8cm)

36cm + 64cm

QR=100

OR=10 cm

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