Question

PQR is a triangle, right angled at Q. If PR = 41 cm and QR = 40 cm . Find PQ

Answer 1

Answer:

PQ²+QR²=PR²

PQ²=PR²-QR²

PQ²=41²-40²

PQ²=1684-1600

PQ=√84

=2√21

Answer 2

Step-by-step explanation:

$in \: triangle \: pqr \: \\ given \frac{.}{.} \: \: pr = 41cm \: \\ \: \: \: \: \: \: \: \: \: qr = 40cm$

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. .

By Pythagoras theorem

${pr}^{2} = {pq}^{2} + {qr }^{2} \\ {41}^{2} = {pq}^{2} + {40}^{2} \\ 1681 = {pq}^{2} + 1600 \\ 1681 - 1600 = {pq}^{2} \\ 81 = {pq}^{2} \\ pq = \sqrt{81 } \\ pq = 9cm$