Question

PQR is a triangle, right angled triangle at p if pq + 10 cm and pr + 24 cm find qr

Answer 1

Answer:

Given: PQ=10cm, PR=24cm

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse)

2

=(Base)

2

+(Perpendicular)

2

[By Pythagoras theorem]

⇒(QR)

2

=(PQ)

2

+(PR)

2

⇒x

2

=(10)

2

+(24)

2

⇒x

2

=100+576=676

⇒x=

676

=26cm

Thus, the length of QR is 26cm.

Step-by-step explanation:

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Answer 2

Answer:

Refer to the attachment above. ⬆️

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