Question

PQR is a triangle. S is any point on a line through P parallel to QR. If T is any point on
a line through R parallel to SQ, then the three triangles equal in area are
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Answer 1

Answer

AnswerIn ΔPQR, we have

AnswerIn ΔPQR, we havePQ=PR⇒∠R=∠Q

AnswerIn ΔPQR, we havePQ=PR⇒∠R=∠QNow, ST∥QR.

AnswerIn ΔPQR, we havePQ=PR⇒∠R=∠QNow, ST∥QR.⇒∠PST=∠PQR and ∠PTS=∠PRQ [∵ Corresponding angles are equal]

AnswerIn ΔPQR, we havePQ=PR⇒∠R=∠QNow, ST∥QR.⇒∠PST=∠PQR and ∠PTS=∠PRQ [∵ Corresponding angles are equal]⇒∠PST=∠Q and ∠PTS=∠R

AnswerIn ΔPQR, we havePQ=PR⇒∠R=∠QNow, ST∥QR.⇒∠PST=∠PQR and ∠PTS=∠PRQ [∵ Corresponding angles are equal]⇒∠PST=∠Q and ∠PTS=∠R⇒∠PST=∠PTS

AnswerIn ΔPQR, we havePQ=PR⇒∠R=∠QNow, ST∥QR.⇒∠PST=∠PQR and ∠PTS=∠PRQ [∵ Corresponding angles are equal]⇒∠PST=∠Q and ∠PTS=∠R⇒∠PST=∠PTS⇒PT=PS