PQR is an equilateral triangle of side a. Find the length of each altitude.
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Answer:
3a²/4
Step-by-step explanation:
Given,
PQ= PR= QR = a
We draw altitude PS perpendicular to QR
In triangle PQS,
PQ²= QS² + PS²___________(i)
SINCE IN AN EQUILATERAL TRIANGLE ALTITUDE AND MEDIAN ARE SAME QS = RS
Therefore QR = 1/2 QS
QS = a/2_______(ii)
From (i) and (ii)
PS² = a² - (a/2)²
PS = √ a² - a²/4
PS= √(4a²-a²)/4
PS = a√3/4
Therefore each of its altitudes are a√3/4
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