∆PQR is an equilateral ∆ with coordinates of Q and R as (-2,0) and (2,0) respectives find the coordinates of vertex P.
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Answered by
9
Answer:
P(0,4)
Step-by-step explanation:
as
on x axis it is 2 units +2units which is 4 units and P is on y axis therefore coordinates of P is (4,0).
Answered by
3
here op is the median,altitude etc
because in equlateral triangle all centers lie on only one point
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