PQR is an isosceles triangle in which PQ=PR. Side QP is produced to such that PS=PQ Show
that QRS is a right angle
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Given :-
- ∆PQR is an isosceles triangle in which PQ=PR.
- Side QP is produced to such that PS = PQ.
Solution :-
Given that, PQ = PR,
So,
→ ∠PQR = ∠PRQ = Let x . (Angle Opp. to Equal sides are Equal.)
Also,
→ PS = PQ (Given.)
Than,
→ PS = PR .
So,
→ ∠PSR = ∠PRS = Let y . (Angle Opp. to Equal sides are Equal.)
Now, in ∆QRS , we have ,
→ ∠SQR + ∠QRS + ∠QSR = 180° .(Angle sum Property.)
→ x + (x + y) + y = 180°
→ 2x + 2y = 180°
→ 2(x + y) = 180°
Dividing both sides by 2,
→ (x + y) = 90°.
Hence,
→ ∠QRS = (x + y) = 90° . (Proved.)
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