Question

pqr is an isosceles triangle in which the base QR is 16 cm long and each side PQ and PR is 10 cm long find the area of the triangle pqr​

Answer 1

Answer:

Answer: AREA=1/2*BASE*

HEIGHT

=> AREA=

1/2*16*6=48cm

Answer 2

Step-by-step explanation:

Find h using Pythagoras

$h = \sqrt{ {10}^{2} - {8}^{2} } = 6$

use formula of area

$area = \frac{1}{2} \times b \times h = \frac{1}{2} \times 6 \times 16 = 48$