Question

PQR is an Isosceles Triangle inscribed in a circle. If PQ=PR =25 cm and QR= 14 cm calculate the radius of the circle to the nearest cm.

Answer 1

Answer:

ans=16

if it is a isosceles triangle and if we draw a median from vertice P to QR it will acts as altitude as well so that means it will be perpendicular

so triangle PQZ, here Z is the point on QR, which is median and altitude

so using Pythagoras

PQ^2=QZ^2+PZ^2

25^2=7^2+PZ^2

625=49+PZ^2

PZ^2=625-49

=576

PZ=24

So the height or median is 24

we know that centroid of a triangle divide 2:1

that means 24 divides in three parts

so

radius is 2 parts so radius is 16

Answer 2

Answer:

ans=16

if it is a isosceles triangle and if we draw a median from vertice P to QR it will acts as altitude as well so that means it will be perpendicular

so triangle PQZ, here Z is the point on QR, which is median and altitude

so using Pythagoras

PQ^2=QZ^2+PZ^2

25^2=7^2+PZ^2

625=49+PZ^2

PZ^2=625-49

=576

PZ=24

So the height or median is 24

we know that centroid of a triangle divide 2:1

that means 24 divides in three parts

so

radius is 2 parts so radius is 16

Step-by-step explanation:

this is the answer hope u understand :D