pqr is an isosceles triangle right angled at r prove that PQ² =2pq²
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as it's a right angle
apply pythagorus
Also isosceles so height and base are equal
so pq)^2 = pr^2 + pr^2
= 2pr)^2
apply pythagorus
Also isosceles so height and base are equal
so pq)^2 = pr^2 + pr^2
= 2pr)^2
Answered by
2
In triangle pqr
Angle r = 90
side rq = rp (isosceles triangle)
pq is the hypotenuse of the triangle
by pythagoras theorem,
we can say that
pq^2 = rq^2 + rp^2
pq^2 = rq^2 + rq^2 (rp = rq)
therefore pq^2 = 2rq^2
hence proved
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