PQR is an isosceles triangle where PQ = QR and S is the midpoint of QR. Prove that PS is the bisector of angle P
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Answered by
2
Answer:
We have,
According to given figure.
PQ=PR(giventhat)
QS=SR(Bydefinationofmidpoint)
PS=PS(Commonline)
Then,
ΔSPQ≅ΔSPR (BY congruency S.S.S.)
Hence, PS bisects ∠PQR by definition of angle bisector.
Answered by
4
Answer:
see the above attachment
Step-by-step explanation:
We have two triangles PQM and PRM.
PQ = PR [given]
QM = MR [M being the midpoint of QR]
PM is common to both.
Hence the two triangles PQM and PRM are congruent [By SSS postulate]
Therefore <QPM = <RPM [ angles opposite equal sides QM and MR], so PM bisects the <QPR.
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