PQR is an isosceles triangle which is inscribed in a circle with center O. If PQ=PR and angle PQR is 35 degree.
then find angle QSR and QTR
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In △PQR, we have
PQ = PR
⇒ ∠PQR = ∠PRQ
⇒ ∠PRQ = 35˚
∴ ∠QPR = 180˚ - (∠PQR + ∠PRQ)
= 180˚ - (35˚ + 35˚) = 110˚.
Since, PQTR is a cyclic quadrilateral.
∴ ∠P + ∠T = 180˚
⇒ ∠T = 180˚ – 110˚ = 70˚
In cyclic quadrilateral QSRT, we have
∠S + ∠T = 180˚
⇒ ∠S = 180˚ - 70˚ = 110˚
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