PQR is right-angled at Q and QR = 5
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In ΔPQR, right-angled at Q. PR+QR=25 cm and PQ=5 cm. Determine the values of sin P, cos P, tan P
Answer
⇒PQ=5cm
⇒PR+QR=25cm
⇒PR=25−QR
Now, In △PQR
⇒(PR)
2
=PQ
2
+QR
2
⇒(25−QR)
2
=5
2
+QR
2
⇒625+QR
2
−50QR=25+QR
2
⇒50QR=600
⇒QR=12cm
⇒PR=25−12=13cm
∴sinP=
PR
QR
=
13
12
,cosP=
PR
PQ
=
13
5
,tanP=
PQ
QR
=
5
12
Hence, the answers are sinP=
13
12
,cosP=
13
5
,tanP=
5
12
.
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