Question

∆PQR is right angled at Q. If sinP = 12/13, then what is the value of tanR ?

A) 5/13 B) 13/5 C) 13/12 D) 5/12

Answer 1

If PQR is right angled at Q and

Sin P= 12/13

Now we know Sin is perpendicular/Hypotenuse ...therefore

P/H = 12/13

Here P = 12 and H = 13

Now it is right angled triangle ,therefore we can easily find the base by Pythagoras theorem.

H^2 = P^2 + B^2

B^2 = H^2 - P^2

B^2 = (13)^2 - (12)^2

B^2 = 169 - 144

B^2 = 25

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Therefore B (base) = 5

Now Tan R = P/B = 5/12

ANSWER IS 5/12

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(NOTE ...HERE WE HAVE TO FIND TAN R..THEREFORE BASE IS 12 AND PERPENDICULAR FOR ANGLE ""R"" IS 5)