PQR is right angled triangle with QR=12cm and PQ=5cm . A circle with center o is inscribed in triangle PQR. find the radius of the circle.
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The radius of the circle is 2 cm
Solution:
From the below diagram:-
RA + AO = 12 ______ (1)
RC + CP = 13 _______ (2)
OB + BP = 5 _______ (3)
Now from the above figure
Side AO = Side OB = Radius of the circle
Side RA = Side RC
Line BP = Line CP
Rewriting these three equations we get
RA + AO = 12 _______ (4)
RA + BP = 13 _______ (5)
AO + BP = 5 _______(6)
(4) – (6) + (5)
RA – BP = 7
RA + BP = 13
2 RA = 20
RA = 10
From equation 4, AO = 12 – 10 = 2 cm
Since AO is equal to radius of the inscribed circle, radius = 2 cm.
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