Question

pqr is right triangle right angled at q find the length of pe if pd=3 qd=2 qr=12
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Answer 1

Answer:

the lenght is

Step-by-step explanation:

2 cm

.........

Answer 2

PR2 = PQ2 + QR2 = 25 + 144 = 169

PR = 13 cm

Let PE = x, then ER = 13 - x

In ΔPQR and ΔPED,

∠PQR = ∠PED

∠QPR = ∠EPD

∴  ΔPQR ≅ PED [AA similarity]

∴PQ/PE = QR/ED = PR/PD

5/x = 12/ED = 13/3

∴ PE= x = 5 × 3 / 13= 15/13 = 1whole 2/13

ED = 12 × 3/ 13 = 36 / 13 = 2 whole 10/13 cm