pqr is right triangle right angled at q find the length of pe if pd=3 qd=2 qr=12
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Answer:
the lenght is
Step-by-step explanation:
2 cm
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PR2 = PQ2 + QR2 = 25 + 144 = 169
PR = 13 cm
Let PE = x, then ER = 13 - x
In ΔPQR and ΔPED,
∠PQR = ∠PED
∠QPR = ∠EPD
∴ ΔPQR ≅ PED [AA similarity]
∴PQ/PE = QR/ED = PR/PD
5/x = 12/ED = 13/3
∴ PE= x = 5 × 3 / 13= 15/13 = 1whole 2/13
ED = 12 × 3/ 13 = 36 / 13 = 2 whole 10/13 cm
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