∆pqr is such that angle p = angle q = angle r = 60° which of the following is true
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ΔPQR is isosceles since PQ = QR. ∴ ∠QPR = ∠QRP = 60° ∠RQT is the exterior angle of ΔPQR which is equal to the sum of interior opposite angles ∠P and ∠R. Hence, ∠RQT = 60° + 60° = 120°.
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