Question

PQR is triangle, right angled at R if PQ= 12 cm and PR= 5 cm Find RQ​

Answer 1

Answer:

A

2 cm

In ΔPQR

(PR)

2

=(PQ)

2

+(QR)

2

(PR)

2

=(12)

2

+(5)

2

(PR)

2

=169

PR=13

Now AOBQ is a square

So, QB=x

Then, BR=5−x

Similarly AQ=x

Then AP=12−x

Also, CR=BR

CR=5−x

[∵ Length of tangents drawn from external point are equal]

And, CP=AP=12−x

[∵ Length of tangents drawn from external point are equal]

PR=PC+CR

13=5−x+12−x

2x=4⇒x=2 cm.

Answer 2

Answer:

The length of PR is 13 cm.

Explananation:

PQR is a right angled triangle

Angle Q=90°

PQ=5 cm

QR= 12 cm

Using Pythagoras Theorem applied to PQR triangle:

PR^2 (Hypotenuse^2)= PQ^2 (Base ^2) + QR^2 (Perpendicular ^2)

=> PR^2=PQ^2+ QR^2

=> PR^2=5^2+12^2

=> PR^2=25+144

=> PR^2=169

=> PR=√169

=> PR=13 cm.