Question

PQR is triangle , right angles at P If PQ =15cm and POR=24cm​

Answer 1

Given: PQ = 10 Cm, PR = 24 Cm

Let QR be x cm.

In right angled triangle QPR,

$(hypotenuse) {}^{2} = (base) {}^{2} + (perpendicular) {}^{2}$

[By Pythagoras theorem]

===> ( QR )² = ( PQ )² + ( PR )²

===> X² = ( 10 )² + ( 24 )²

===> X = √676 = 26 Cm.

Thus, the length of QR is 26 cm.