Question

PQR = LMN, Q = M= 90, PQ = 4cm and QR = 3 cm. find LN.​

Answer 1

Step-by-step explanation:

∆PQR=∆LMN.........(1)

Q = R = 90

PQ=4

QR=3

SO,

${pr}^{2} = {pq}^{2} + {qr}^{2} \\ {pr}^{2} = {4}^{2} + {3}^{2} \\ {pr}^{2} = 16 +9 \\ {pr}^{2} = 25 \\ pr = \sqrt{25} \\ pr = 5 </strong><strong>></strong><strong>></strong><strong>></strong><strong>></strong><strong>></strong><strong>></strong><strong>></strong><strong>></strong><strong>></strong><strong>></strong><strong>\\ </strong><strong>now \: pqr = lmn \: so \: all \: angle \: and \: side \: are \: equle \\ so \: pr = ln \: (from \: \: \: \: 1)$