Question

∆PQR <p=76, <Q =48 ,<R= ?​

Answer 1

Answer:

angle R=56

triangle PQR= 180°

angle P + angle Q +angle R= 180°

76°+48°+R=180°

180°-124°=R

56°=R

Answer 2

$\huge\sf \green{\underline{\red{\underline{\blue{\underline{\orange{Given :-}}}}}}}$

1. ∆PQR
2. ∠P = 76°
3. ∠Q = 48°

$\huge\sf \green{\underline{\red{\underline{\blue{\underline{\orange{To \: Find :-}}}}}}}$

• ∠R = ?

$\huge\sf \green{\underline{\red{\underline{\blue{\underline{\orange{Solution :-}}}}}}}$

★ We know that all the angles of triangle = 180° ★

So,

∠P + ∠Q + ∠R = 180°

➱ 76° + 48° + ∠R = 180°

➱ 124° + ∠R = 180°

➱ ∠R = 180° - 124°

➱ ∠R = 56°

Hence,

∠R = 56°