Question

*∆ PQR मध्ये PQ = 10 सेमी , QR = 6 सेमी , PR = 8 सेमी ∆ LMN मध्ये LM = 5 सेमी , MN = 3 सेमी , LN = 4सेमी तर दोन्ही त्रिकोण कोणत्या कसोटी ने समरूप होतील.*​

Answer 1

Given : ∆ PQR मध्ये PQ = 10 सेमी , QR = 6 सेमी , PR = 8 सेमी

∆ LMN मध्ये LM = 5 सेमी , MN = 3 सेमी , LN = 4सेमी  

To Find :  दोन्ही त्रिकोण कोणत्या कसोटी ने समरूप होतील.*

1️⃣ बाबाबा 2️⃣ बाकोबा 3️⃣ कोकोको 4️⃣ कोबाको

SSS , SAS  , AAA , ASA

Solution:

∆ PQR मध्ये PQ = 10 सेमी , QR = 6 सेमी , PR = 8 सेमी

∆ LMN मध्ये LM = 5 सेमी , MN = 3 सेमी , LN = 4सेमी  

PQ/LM = 10/5 = 2

QR/MN = 6/3 = 2

PR/LN  = 8/4 = 2

=> PQ/LM   = QR/MN  = PR/LN

Hence ∆ PQR  ~ ∆ LMN  (SSS similarity )

Side side side similarity

बाबाबा

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