Question

Δ PQR मध्ये ∠Q = 90°, PQ = 12, QR = 5 आणि QS ही PR ची मध्यगा असेल तर QS काढा.

Answer 1

Answer: QS= 6.5

Step-by-step explanation: by Pythagoras theorem,

(PR)^2=(PQ)^2+(QR)^2

(PR)^2= 144+25

(PR)^2=169

PR= 13. PR/2=13/2=6.5

So by geometric mean theorem,

QS^2=PS×SR

QS^2=6.5×6.5

QS= 6.5