Question

pqr (p + q + r) – pq (rq + pq) + 2 (p² q + pqr²) ​

Answer 1

Answer:

−p2q2+p2qr+3pqr2+2p2q

Step-by-step explanation:

Distribute:

=(pqr)(p)+(pqr)(q)+(pqr)(r)+−p2q2+−pq2r+(2)(p2q)+(2)(pqr2)

=p2qr+pq2r+pqr2+−p2q2+−pq2r+2p2q+2pqr2

Combine Like Terms:

=p2qr+pq2r+pqr2+−p2q2+−pq2r+2p2q+2pqr2

=(−p2q2)+(p2qr)+(pq2r+−pq2r)+(pqr2+2pqr2)+(2p2q)

=−p2q2+p2qr+3pqr2+2p2q