Question

∆PQR, PE is the perpendicualr bisector of ∠QPR then prove that PQ = PR.​

Answer 1

Step-by-step explanation:

In triangles PEQ and PER

PE=PE(common)

∠PEQ=∠PER

QE=RE

Thus by ASA congruency, △PEQ and △PER are congruent.

By cpct, PQ=PR.