Question

∆PQR~ ∆PMN IN ∆PQR PQ=4CM QR=5CM PR=6CM CONTRUCT ∆PQR AND ∆PMN SUCH THAT PR/PN=3/5 ​

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Class 7

>>Maths

>>Practical Geometry

>>Constructions of Triangles

>>Construct a triangle PQR , given that PQ

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Construct a triangle PQR, given that PQ=4cm,QR=5.2cm and ∠Q=60

∘

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Solution

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Steps of Construction:

(i) Draw a line segment that is sufficiently long using a ruler.

(ii) Locate points Q and R on it such that QR=5.2cm.

(iii) At Q, construct a line segment QM, sufficiently large, such that ∠MQR at 60

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use protractor to measure 60

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(iv) With Q as centre and radius 4cm, draw the line cutting QM at P, join PR.

Then PQR is the required triangle.