Math, asked by 9526976024av, 1 year ago

∆PQR, Q = 90° ,PR = 10√2 cm and QR = 10 cm find the value of sec P, cot P and cosec p.

Answers

Answered by saicharanstar22

1

Secp =√2

Cos p=√2

Cosec p =√2

saicharanstar22: Cot p =1

9526976024av: Details

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