∆pqr,r=5q=3(p+q)find all angles of?∆pqr
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in triangle pqr, given,
r=5q
5q=3[p+q]
which means,
5q=3p+3q => 2q=3p => p=2q/3
so p+q+r=180 as we know.
2q/3 + q + 5q = 180
=> 20q/3 = 180.
=> 20q = 540
=> q = 27degrres.
r=5q=5*27= 135degrees.
p=2q/3= 2*27/3 = 18degrees.
therefore, the angles are 27,135 and 18.
r=5q
5q=3[p+q]
which means,
5q=3p+3q => 2q=3p => p=2q/3
so p+q+r=180 as we know.
2q/3 + q + 5q = 180
=> 20q/3 = 180.
=> 20q = 540
=> q = 27degrres.
r=5q=5*27= 135degrees.
p=2q/3= 2*27/3 = 18degrees.
therefore, the angles are 27,135 and 18.
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