Math, asked by jadahchristineogendo, 11 months ago

pqr+rpq+qrq+2pq is equal to???

Answers

Answered by Anonymous
0

Answer:

2pqr + q^2×r + 2pq

2pq(r + 1) + q^2×r

hope this helps you...

Answered by AdorableMe
45

Answer:

3pq+2pq

Step-by-step explanation:

We know,

pqr=rpq=qrp

So,

pqr+rpq+qrq+2pq = 3pqr+2pq

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