△PQR, ST || QR. If ST = 3cm ,QR = 6cm and ar(PST) = 15cm2
, Find area of
△PQR.
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2
Answer:
ST∥QR [ Given ]
∴
PQ
PS
=
PR
PT
[ By BPT ]
⇒
SQ
PS
=
5
3
and PR=28cm [ Given ]
⇒
PS
SQ
=
3
5
⇒
PS
SQ+PS
=
3
5+3
∴
PS
PQ
=
3
8
⇒
PQ
PS
=
8
3
⇒
PQ
PS
=
PR
PT
⇒
8
3
=
28
PT
⇒ PT=
8
28×3
∴ PT=10.5cm
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